Step 1: Use the equation for angular position: θf = θi + ωi*t + 1/2*α*t^2
Step 2: Substitute the given values into the equation: θf = 2.3 rad + (1.5 rad/s)*2.0 s + 1/2*(-0.40 rad/s^2)*(2.0 s)^2
Step 3: Simplify the equation: θf = 2.3 rad + 3.0 rad - 0.8 rad
Step 4: Calculate the final angular position: θf = 4.5 rad
At t = 0, a wheel rotating about a fixed axis at a constant angular acceleration of –0.40 rad/s^2 has an angular velocity of 1.5 rad/s and an angular position of 2.3 rad. What is the angular position of the wheel
at t = 2.0 s? Ans: Theta final=4.5 rad
How do you solve step by step. Thanks
Does this look correct below?
Of = Oi+Wi*t+1/2*a*t^2
Of = 2.3rad+(1.5 rad⁄s(2.0s)+0.5(-0.40 rad⁄s^2)(2.0s)
Of = 2.3 rad + 3.0 rad - 0.8 rad
Of = 4.5 rad
Thanks! Bob Pursley, This helped me solve it and here is the step by step break down.
1 answer