A wheel 1.0m in diameter is rotating about a fixed axis with an initial angular velocity of 2rev.s-1.the angular acceleration is 3rev.s-1.
(1)compute the angular velocity after 6s.
(2)through what angle has the wheel turned in this time interval?
(3)what is the tangenial velocity of a point on the rim of the wheel at t=6s?
3 answers
Plss naww
Plss naww I need help
acceleration is in s^-2
(1) 2rps + (3 rps^2 * 6 s) = 20 rps
(2) ave rps = (2 + 20) / 2 = 11rps
... 11 rps * 6 s = 66 rev ... 2π rad per rev
(3) tan vel is ... 20 rps * circumference
... circumference is π times diameter
(1) 2rps + (3 rps^2 * 6 s) = 20 rps
(2) ave rps = (2 + 20) / 2 = 11rps
... 11 rps * 6 s = 66 rev ... 2π rad per rev
(3) tan vel is ... 20 rps * circumference
... circumference is π times diameter
3 answers