............H2 + I2 ==> 2HI
I......0.0600...0.0300...0
C.........-x.....-x......+2x
E.......0.06-x...0.03-x...2x
Substitute the E line into the Keq expression and solve for x. Then
H2 = 0.06-x
I2 = 0.03-x
HI = 2x
At some temperature, Keq = 33 for the reaction H2 + I2 „³ 2HI. If initially, [H2] = .0600 M and [I2] = .0300 M, what are all three equilibrium concentrations?
1 answer