(a) Let C be the unknown cost of tuna (in dollars). Using the values given, the proportion can be set up as:
12 kg / $54 = 2 kg / C
(b) To find the cost of 2 kilograms of tuna using the proportion above, we can cross-multiply and solve for C:
12 kg * C = 2 kg * $54
12C = $108
Dividing both sides of the equation by 12:
C = $9
Therefore, the cost of 2 kilograms of tuna is $9.
At Fumiko's Fish Market, it costs $54 for 12 kilograms of tuna. At this rate, how much does it cost for 2 kilograms of tuna?
(a) Let C be the unknown cost of tuna (in dollars). Using the values below, create a proportion that can be used to find C.
Values:
_____ _____
(b) Use the proportion from part (a) to find the cost of 2 kilograms of tuna. Do not round any computations.
5 answers
Suppose a satellite orbiting Earth travels 70 kilometers in 8 seconds. At this rate, how far does it travel in 40 seconds?
(a) Let d be the unknown distance the satellite travels (in kilometers). Using the values below, create a proportion that can be used to find d.
Values: d , 70 , 8 , 40
_____ _____
(b) Use the proportion from part (a) to find the distance the satellite travels in 40 seconds. Do not round any computations.
(a) Let d be the unknown distance the satellite travels (in kilometers). Using the values below, create a proportion that can be used to find d.
Values: d , 70 , 8 , 40
_____ _____
(b) Use the proportion from part (a) to find the distance the satellite travels in 40 seconds. Do not round any computations.
(a) Let d be the unknown distance the satellite travels (in kilometers). Using the values given, the proportion can be set up as:
70 km / 8 sec = d km / 40 sec
(b) To find the distance the satellite travels in 40 seconds using the proportion above, we can cross-multiply and solve for d:
70 km * 40 sec = 8 sec * d km
2800 km-sec = 8d km-sec
Dividing both sides of the equation by 8 sec:
350 km = d km
Therefore, the satellite travels a distance of 350 kilometers in 40 seconds.
70 km / 8 sec = d km / 40 sec
(b) To find the distance the satellite travels in 40 seconds using the proportion above, we can cross-multiply and solve for d:
70 km * 40 sec = 8 sec * d km
2800 km-sec = 8d km-sec
Dividing both sides of the equation by 8 sec:
350 km = d km
Therefore, the satellite travels a distance of 350 kilometers in 40 seconds.
A crew is building a sidewalk. It can build a length of 3 kilometers in 5 days. At this rate, how much time would it take it to build 24 kilometers of sidewalk?
(a) Let t be the unknown amount of time it would take the crew (in days). Using the values below, create a proportion that can be used to find t.
Values: t , 3 , 5, 24
_____ _____
(b) Use the proportion from part (a) to find the time it would take the crew to build 24 kilometers of sidewalk. Do not round any computations.
(a) Let t be the unknown amount of time it would take the crew (in days). Using the values below, create a proportion that can be used to find t.
Values: t , 3 , 5, 24
_____ _____
(b) Use the proportion from part (a) to find the time it would take the crew to build 24 kilometers of sidewalk. Do not round any computations.
(a) Let t be the unknown amount of time it would take the crew (in days). Using the values given, the proportion can be set up as:
3 km / 5 days = 24 km / t days
(b) To find the time it would take the crew to build 24 kilometers of sidewalk using the proportion above, we can cross-multiply and solve for t:
3 km * t days = 24 km * 5 days
3t = 120
Dividing both sides of the equation by 3:
t = 40
Therefore, it would take the crew 40 days to build 24 kilometers of sidewalk.
3 km / 5 days = 24 km / t days
(b) To find the time it would take the crew to build 24 kilometers of sidewalk using the proportion above, we can cross-multiply and solve for t:
3 km * t days = 24 km * 5 days
3t = 120
Dividing both sides of the equation by 3:
t = 40
Therefore, it would take the crew 40 days to build 24 kilometers of sidewalk.