At body temperature (37C), K of an enzyme-catalyzed reaction is 2.3x10^14 times greater than k of the uncatalyzed reaction. Assuming that the frequency factor A is the same for both reaction, by how much does the enzyme the E^a?

Question

At body temperature (37C), K of an enzyme-catalyzed reaction is 2.3x10^14 times greater than k of the uncatalyzed reaction. Assuming that the frequency factor A is the same for both reaction,  by how much does the enzyme the E^a?

DrBob222 · Answer

ln 2.3E14 = -Ea/RT Solve for Ea