V(p) = 1/p
V(6) = 1/6
V(7) = 1/7
ΔV = V(7) - V(6) = 1/7 - 1/6 = -1/42
Δp = 7 - 6 = 1
a)Average rate of change:
ΔV/Δp = (-1/42)/1 = -1/42 Liter/atmosphere
At a temperature of 20°C, the volume V (in liters) of 1.33 g of O2 is related to its pressure p (in atmospheres) by the formula
V(p) = 1/p
(a) What is the average rate of change of V with respect to p as p increases from p = 7 to p = 8?
L/atm
(b) What is the rate of change to V with respect to p when p = 7?
L/atm
2 answers
V(p) = 1/p
V(6) = 1/6
V(7) = 1/7
ΔV = V(7) - V(6) = 1/7 - 1/6 = -1/42
Δp = 7 - 6 = 1
a)Average rate of change:
ΔV/Δp = (-1/42)/1 = -1/42 Liter/atmosphere
Actual rate of change
dV/dp = -1/p²
At p = 6
dV/dp = -1/6² = -1/36 L/atm
V(6) = 1/6
V(7) = 1/7
ΔV = V(7) - V(6) = 1/7 - 1/6 = -1/42
Δp = 7 - 6 = 1
a)Average rate of change:
ΔV/Δp = (-1/42)/1 = -1/42 Liter/atmosphere
Actual rate of change
dV/dp = -1/p²
At p = 6
dV/dp = -1/6² = -1/36 L/atm
1 answer