A sample of gas with a volume of 14.9 liters at 2.6 atmospheres pressure and a temperature of 25°C is allowed to expand to a volume of 29.3 liters at a temperature of 15°C. What is the final pressure (atm)atof the gas?
2 answers
See your other posts.
PV=nRT
14.9L*2.6atm=n*0.08206*(25+273.15)
n=1.583mol
PV=nRT
P*29.3L=1.583mol*(15+273.15)*0.08206
P=1.2778atm
14.9L*2.6atm=n*0.08206*(25+273.15)
n=1.583mol
PV=nRT
P*29.3L=1.583mol*(15+273.15)*0.08206
P=1.2778atm
2 answers