At a pressure 43 kPa, the gas in a cylinder has a volume of 11 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 5 liters, what is the new pressure?

Question

kPa
Im guessing it 58 or 77x10^3

Answer 1

PV=kT
so, since T is constant, so is PV. You want P such that

P*5 = 43*11
P = 94.6