work = -P(V2-V1)
Work = -8.00(0.500-0.130) in units of L*atm.
You can convert to Joules by
L*atm x 101.325 = Joules. Approximately 340 J.
A piston has an external pressure of 9.00 atm. How much work has been done if the cylinder goes from a volume of 0.130 liters to 0.500 liters? can someone explain to me how am i supposed to do this please? Thanks :D
1 answer
1 answer