It can gain potential energy equal to the kinetic energy at the bottom of the swing.
M g H = (M/2) V^2
H = V^2/(2*g)
You don't need to know the mass.
At a low point in its swing, a pendulum bob with a mass of 0.2kg has a velocity of 4m/s. Ignoring air resistance, how high will the bob swing above the low point before reversing direction?
Please explain and show work.
1 answer