Let's say the number of aerobics classes is x.
For members, the cost is the membership fee plus $4 for each class:
Cost for members = $10 + $4x
For nonmembers, the cost is $5 for each class:
Cost for nonmembers = $5x
We need to find the value of x for which the cost for members and nonmembers is the same:
$10 + $4x = $5x
Rearranging the equation:
$4x - $5x = -$10
-$x = -$10
x = 10
Therefore, for 10 aerobics classes, the cost for members and nonmembers will be the same.
At a local fitness center, members pay a $10 membership fee and $4 for each aerobics class. Nonmembers pay $5 for each aerobics class. For what number of aerobics classes will the cost for members and nonmembers be the same?
(Type in a whole number)
3 answers
Solve the system by graphing. Tell whether the system has one solution, infinitely many solutions, or no solution.
y - x = 5
4y = 4x + 20
y - x = 5
4y = 4x + 20
Let's rearrange each equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
First equation:
y - x = 5
Rearranging, we get: y = x + 5
Second equation:
4y = 4x + 20
Dividing both sides by 4, we get: y = x + 5
Comparing both equations, we can see that they are the same equation. The system is graphed as a single line.
This means that the system has infinitely many solutions since any point on the line satisfies both equations.
First equation:
y - x = 5
Rearranging, we get: y = x + 5
Second equation:
4y = 4x + 20
Dividing both sides by 4, we get: y = x + 5
Comparing both equations, we can see that they are the same equation. The system is graphed as a single line.
This means that the system has infinitely many solutions since any point on the line satisfies both equations.