...........H2 + I2 ==> 2HI
I.........0.50.0.50....0
C.........-x....-x.....2x
E........0.50-x.0.50-x..2x
Substitute the E line into Kc expression and solve for x, then 0.50-x and 2x.
At a certain temperature, the Equilibrium constant, Kc, for this reaction is 53.3. At this temperature, 0.500 mol of H2 and 0.500 mol of I2 were placed in a 1.00-L container to react. What concentration of HI is present at Equilibrium?
equation: H2 + I2 = 2HI
2 answers
Those of you looking at this in the future don't forget the quadratic equation!!!