At a certain temperature, the equilibrium

Question

constant Kc is 0.154 for the reaction
2 SO2(g) + O2(g) *) 2 SO3(g)
What concentration of SO3 would be in
equilibrium with 0.250moles of SO2 and 0.578
moles of O2 in a 1.00 liter container at this
temperature? Note: These latter moles are
the equilibrium values.
Answer in units of M.

Answer 1

2SO2 + O2 ==> 2SO3
K = 0.154 = (SO3)^2/(SO2)^2(O2)
Plug in SO2 and O2 equilibrium values and solve for the only unknown (SO3) you have.

Answer 2

I got .3335640868, it said I was wrong.

Answer 3

.004

Answer 4

2SO2 + O2 ==> 2SO3
K = 0.154 = (SO3)^2/(SO2)^2(O2)
0.154 = (SO3)^2 / (0.250)^2 * 0.578
0.006843375 = (SO3)^2
(SO3) = 0.082724694