Z = (score - mean)/SD
Z = (58.5-62)/ 3.5 = -1
Z = (72.5-62)/3.5 = 3
It goes from one standard deviation below the mean to 3 above.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to those Z scores.
Assuming that the heights of college women are normally distributed with mean 62 inches and standard deviation 3.5 inches, what percentage of women are between 58.5 inches and 72.5 inches?
34.1%
84.0%
15.7% my answer was 13.6
13.6% is this correct
97.6%
3 answers
my answer is equals 15.7 is this correct
Assuming that the heights of college women are normally distributed with mean 62 inches and standard deviation 3.5 inches, what percentage of women are between 58.5 inches and 72.5 inches?
a. 13.6%
b. 84.0%
c. 97.6%
d. 34.1%
e. 15.7%
a. 13.6%
b. 84.0%
c. 97.6%
d. 34.1%
e. 15.7%