Assuming that the heights of college women are normally distributed with mean 66 inches and standard deviation 2 inches, what percentage of women are shorter than 72 inches?

Answer 1

Try z-scores:

z = (x - mean)/sd

x = 72
mean = 66
sd = 2

Calculate the z-score, then check a z-table for your probability (remember the question is asking "what percentage of women are shorter than 72 inches" when looking at the table).