Assuming that sea water is a 3.5 wt % solution of NaCl in water, calculate its osmotic pressure at 20°C. The density of a 3.5% NaCl solution at 20°C is 1.023 g/mL.

2 answers

3.5% NaCl = 3.5 g NaCl/(3.5g NaCl + 96.5g H2O).
Convert 96.5g H2O to mL using the density.
Calculate M (= moles/L) from 3.5 g NaCl in ?? mL H2O and plug in M for equation
pi = i*M*RT
i for NaCl will be 2. Post your work if you get stuck.
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