.5(k)x^2=m(9.81)(d)(mk)
mk=coefficient of friction
d= is distance traveled
m=is mass of albertine in kg
x=distance spring was displaced
k=spring constant
so enter in everything you do know and solve for mk.
answer: mk=.102
Assuming that Albertine's mass is 60.0 , what is , the coefficient of kinetic friction between the chair and the waxed floor? Use = 9.80 for the magnitude of the acceleration due to gravity. Assume that the value of found in Part A has three significant figures.
Note that if you did not assume that has three significant figures, it would be impossible to get three significant figures for , since the length scale along the bottom of the applet does not allow you to measure distances to that accuracy with different values of .
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