weight = 5*9.81
max static friction force =5*9.81*.8
= 39.24 N
5*9.81 * .22 = 10.8 moving friction
39.24 - 10.8 = 5 a
a = 5.69 m/s^2
A trash can with a mass of 5 kg has a coefficient of static friction of μs = 0.80 and a coefficient of kinetic friction of μk = 0.22. (The Active Figure applies to a similar situation, but the values of the mass, coefficient of static friction and coefficient of kinetic friction may be different. So the values it gives may not be the same values you obtain from your calculations.)
(A) What is the maximum horizontal force Farrowbold that can be exerted without moving the trash can?
(B) Suppose this force is just barely exceeded. Determine the acceleration of the trash can as it moves.
1 answer
1 answer