Assume you poured 5.00 g of KOH in 250 mL of pure water. What is the molarity of the solution you made?

Answer 1

1 mole of KOH=56.11g

and

250mL=0.250L

Solve for moles:

5.00g*(1 mole/56.11g)= moles of KOH

Molarity=moles/volume (L)