c. z = (100-120)/(200sqrt(120*.4)
z = (110-120)/200/sqrt(120*.4))
d. z = (130-120)/200/sqrt((120*.4))
Use Z table
Assume a binomial probability distribution has p = .60 and n = 200.
c. What is the probability of 100 to 110 successes (to 4 decimals)?
d. What is the probability of 130 or more successes (to 4 decimals)?
1 answer