from t = 0 to t = .02 she goes(.21 - .043) = .167
.167 m / .02 seconds = 8.35 m/s
as Sue runs, her knee joint passes through the following vertical positions (meters):
Frame 1: .043
Frame 2: .145
Frame 3: .21
Frame 4: .39
Frame 5: .415
The data were collected at a frequency of 100 Hz. What was the vertical velocity of her knee joint at the 2nd time point?
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