Let \( x \) represent the number of pages Taylor read.
According to the problem, Arlene read 30 pages, which is 10 pages more than half the number of pages Taylor read. This can be expressed as:
\[ 30 = \frac{1}{2}x + 10 \]
To write this in the form \( px + q = r \), we can first rearrange the equation. We will start by isolating the term that includes \( x \).
- Subtract 10 from both sides:
\[ 30 - 10 = \frac{1}{2}x \]
This simplifies to:
\[ 20 = \frac{1}{2}x \]
- Next, we can eliminate the fraction by multiplying both sides by 2:
\[ 2 \cdot 20 = x \]
This simplifies to:
\[ 40 = x \]
Now, we can rewrite the original equation \( 30 = \frac{1}{2}x + 10 \) in the desired form by reorganizing it:
\[ \frac{1}{2}x - 30 + 10 = 0 \] or simply, \[ \frac{1}{2}x - 20 = 0 \]
Thus, in the form \( px + q = r \):
\[ \frac{1}{2}x - 20 = 0 \]
In the equation \( px + q = r \):
- \( p = \frac{1}{2} \)
- \( q = -20 \)
- \( r = 0 \)
So, the completed equation would be:
\(\frac{1}{2}x - 20 = 0\)
Answer in the form requested:
\[ \frac{1}{2} x - 20 = 0 \]