Let's denote the number of pages Taylor read as \( x \).
According to the problem, Arlene read 30 pages, which is 10 pages more than half of what Taylor read. We can express this relationship mathematically.
First, half of the pages Taylor read can be expressed as \( \frac{x}{2} \).
Since Arlene read 10 pages more than this amount, we can write the equation as:
\[ 30 = \frac{x}{2} + 10 \]
Now, to put this into the requested form \( px + q = r \), we can manipulate the equation. Let's multiply through by 2 to eliminate the fraction:
\[ 2 \cdot 30 = 2 \cdot \left(\frac{x}{2} + 10\right) \]
This simplifies to:
\[ 60 = x + 20 \]
Now, we can rearrange this equation to the form \( px + q = r \):
\[ x - 60 + 20 = 0 \]
Which gives us:
\[ x - 20 = -60 \]
So we can state our equation as follows:
\[ 1x - 20 = -60 \]
Therefore, in the format \( px + q = r \), we have:
- \( p = 1 \)
- \( q = -20 \)
- \( r = -60 \)
Thus, the complete equation in the requested format is:
\[ 1x - 20 = -60 \]
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