are these names correct? i'm not sure if i did the anion/cation right..

Question

***numbers are subscripts

1. Rb[AgF4]=
Rubidium tetrafluoroargentate

2. [Ir(CO)Cl(PPh3)2]
=

3. [Co(en)2CO3]Cl=
bisethylenediamine tricarbonyl cobalt (I) chloride

4. Cr(H20)3Br3=
triaqua chromium (III) tribromide

5. [Co(en)2(NH3)Cl]Cl2=
ammine chloro bisethylenediamine cobalt (III) chloride

6. Pt(NH3)2Cl2=
diammine dichloro plantium(II)

7.Na2[NiCl2(H20)2]=
diaqua dichloro nickel disodium

thank you!!!

Answer 1

I think on 1 that you should add the stock notation (I) for argentate and add the word ion. (Rb is +1, Ag+1 and F-4 so the ion is -2.
For #3, I wonder if you have it typed correctly. If we name as is, then CO is carbonyl. CO3 is carbonate (named as carbonato). The ethylenediamine name should be enclosed in parentheses as in bis(ethylenediamine). If we make Co +2 and CO3 is -2 and Cl is -1, that would make the charge on the ion -1 if I didn't goof. So you need to make that Cobaltate(II) and add the word ion

Answer 2

2. I don't know what Ph stands for (perhaps phenyl) and what is the (PPh)3 unit.
4. You have named this as a compound but it carries a charge of -2 making it an anion. If that is correct, you need to name it has an anion meaning as a chromate(I). (Check that. If Cr; is +1 and Br is -3, that would leave -2 for the charge).

Answer 3

All of the anions must end in the metal + ate + (?) such as cuprate(II), chromate(III), ferrate(II), etc. It appears to me that you have written all of them as anions. If so then #1 is the only one named correctly. I hope the notes above gives you some idea how to restructure the names.

Answer 4

It just occurred to me that you may have meant the = sign after each of the problems to indicate an equal sign; that is, the formula listed = ?? and the answer is to follow. That would make a lot more sense and and simplify names considerably. Please clarify if you don't have these figured out yet.

Answer 5

bis(en)Co(III)- μ-amido- μ-hydoxobis(en)Co(II)ion