To simplify the expression \( \frac{4^0 \cdot 5^{-2}}{(-2)^{-3}} \) using the Properties of Integer Exponents, let's first deal with each part of the expression:
-
Evaluate \( 4^0 \): \[ 4^0 = 1 \]
-
Handle \( 5^{-2} \): \[ 5^{-2} = \frac{1}{5^2} = \frac{1}{25} \]
-
Handle \( (-2)^{-3} \): \[ (-2)^{-3} = \frac{1}{(-2)^3} = \frac{1}{-8} = -\frac{1}{8} \]
Now substituting back into the original expression: \[ \frac{4^0 \cdot 5^{-2}}{(-2)^{-3}} = \frac{1 \cdot \frac{1}{25}}{-\frac{1}{8}} \]
Let's simplify \( \frac{\frac{1}{25}}{-\frac{1}{8}} \): \[ \frac{\frac{1}{25}}{-\frac{1}{8}} = \frac{1}{25} \cdot -8 = -\frac{8}{25} \]
Thus, the expression simplifies to: \[ -\frac{8}{25} \]
This is the final result. Therefore, the answer is: \[ \boxed{-\frac{8}{25}} \]