Asked by Karen
Anyone help me?? :)
How to solve:
5x2 = -(19/2x-1)
and
2x2 + 45/2x - 18 = 0
With full solutions? Thank you :)
How to solve:
5x2 = -(19/2x-1)
and
2x2 + 45/2x - 18 = 0
With full solutions? Thank you :)
Answers
Answered by
PsyDAG
First of all, online "^" is used to indicate an exponent, x^2 = x squared.
5x^2 = -(19/2x-1)
Get rid of the parenthesis and multiply by 2.
10x^2 = -19x + 2
Move all terms to left side.
10x^2 + 19x - 2 = 0
Factor the two end values into two factors that will add to the middle value.
(10x-1)(x+2) = 0
X = -2, 1/10
Use a similar process with the second equation.
5x^2 = -(19/2x-1)
Get rid of the parenthesis and multiply by 2.
10x^2 = -19x + 2
Move all terms to left side.
10x^2 + 19x - 2 = 0
Factor the two end values into two factors that will add to the middle value.
(10x-1)(x+2) = 0
X = -2, 1/10
Use a similar process with the second equation.
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