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Answer to david has scores of 79, 96, 63, 54 on his algebra tests. Use an inequality to find the minimum score he can make on the final exam to pass the course with an average of 70 or higher, given that the final counts as 3 tests.

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Mean = ∑x/n

70 ≤ (79+96+63+54+x)/5

Solve for x.

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