One chip drawn would have to be 5 and that probability is 1/8. The probability that a second drawn chip is not larger than 5 is 4/7. The probability of the third chip not being larger than 5 is 3/6, or 1/2. This is true regardless of the order they are drawn.
Total probability = (1/8)*(1/2)*(4/7) = 1/28
An urn contains 8 chips, numbered 1 through 8. A sample of 3 is drawn without replacement. What is the probability that the largest chip in the sample is a 5?
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