Specific heat = (0.125 kg)(98.0°C - 32.0°C) / [(0.285 kg)(32.0°C - 30.0°C) + (0.150 kg)(32.0°C - 30.0°C)]
Specific heat = 0.845 J/g°C
An unknown substance has a mass of 0.125 kg and an initial temperature of 98.0°C. The substance is then dropped into a calorimeter made of aluminum containing 0.285 kg of water initially at 30.0°C. The mass of the aluminum container is 0.150 kg, and the temperature of the calorimeter increases to a final equilibrium temperature of 32.0°C. Assuming no thermal energy is transferred to the environment, calculate the specific heat of the unknown substance.
1 answer
2 answers