To interpret the vertex of the given quadratic function \( h = 6t^2 - 24t + 30 \), we need to identify the vertex, which represents the maximum height of the owl as it swoops down.
The vertex can be found using the formula for the \( t \)-coordinate of the vertex, given by \( t = -\frac{b}{2a} \), where \( a \) is the coefficient of \( t^2 \) and \( b \) is the coefficient of \( t \).
Here, \( a = 6 \) and \( b = -24 \).
Plugging into the formula:
\[ t = -\frac{-24}{2 \times 6} = \frac{24}{12} = 2 \]
Next, we substitute \( t = 2 \) back into the original equation to find the \( h \)-coordinate of the vertex:
\[ h = 6(2)^2 - 24(2) + 30 \] \[ h = 6(4) - 48 + 30 \] \[ h = 24 - 48 + 30 \] \[ h = 6 \]
Thus, the vertex is at the point \( (2, 6) \).
This means that at \( t = 2 \) seconds, the owl reaches its maximum height of 6 feet.
The best interpretation of the vertex is:
d. (2, 6).