To find the vertex of the parabola given by the equation \( h = -6t^2 - 24t + 20 \), we will use the formula for the vertex of a quadratic function, which is given by:
\[ t = -\frac{b}{2a} \]
where \( a \) and \( b \) are the coefficients from the quadratic equation in the form \( at^2 + bt + c \).
From the equation \( h = -6t^2 - 24t + 20 \):
- \( a = -6 \)
- \( b = -24 \)
Plugging in these values into the vertex formula:
\[ t = -\frac{-24}{2 \times -6} = \frac{24}{-12} = -2 \]
Now that we have the \( t \)-coordinate of the vertex, we will find the corresponding \( h \)-coordinate by plugging \( t = -2 \) back into the original equation:
\[ h = -6(-2)^2 - 24(-2) + 20 \] \[ h = -6(4) + 48 + 20 \] \[ h = -24 + 48 + 20 \] \[ h = 24 \]
So the vertex of the parabola is at the point:
\[ (-2, 24) \]
Considering the given options for the vertex, it seems none of the provided answers match this vertex. If we strictly look for the closest matches, the option that might be sought after could just be a misrepresentation or typo in the problem.
However, be sure to verify the vertex computations, as your correct vertex ended up being at \((-2, 24)\).