To interpret the vertex of the quadratic function \( h = 6t^2 - 24t + 30 \), we first need to find the vertex using the formula for the vertex of a parabola \( t = -\frac{b}{2a} \), where \( a \) and \( b \) are the coefficients from the standard form \( h = at^2 + bt + c \).
In your function, we can identify:
- \( a = 6 \)
- \( b = -24 \)
Plugging these values into the vertex formula gives us:
\[ t = -\frac{-24}{2 \cdot 6} = \frac{24}{12} = 2 \]
Now, we need to find the corresponding height \( h \) when \( t = 2 \):
\[ h = 6(2^2) - 24(2) + 30 \] \[ h = 6(4) - 48 + 30 \] \[ h = 24 - 48 + 30 \] \[ h = 6 \]
Thus, the vertex of the function is at the point \( (2, 6) \).
Now, let's interpret this vertex:
- The \( t \)-coordinate (2) represents the time in seconds when the owl's height is at its maximum.
- The \( h \)-coordinate (6) represents the maximum height (in feet) that the owl reaches at that time.
So, the vertex \( (2, 6) \) indicates that at 2 seconds, the owl reaches a height of 6 feet. This means it drops down from a starting height of 30 feet to its lowest point, which is 6 feet.
Therefore, the best interpretation of the vertex is:
(2, 6).