Asked by Coreen
An organ pipe is open at both ends. It is producing sound at its sixth harmonic, the frequency of which is 257 Hz. The speed of sound is 343 m/s. What is the length of the pipe
The open pipe has to be of length lambda/2, and odd number.
Fundamental L= fundamentallambda/2
second harmonic L= 3*fundamentallambda/2
third L = 5*fundamentallambda/2
etc.
fundamentallambda= speedsound/freq
The open pipe has to be of length lambda/2, and odd number.
Fundamental L= fundamentallambda/2
second harmonic L= 3*fundamentallambda/2
third L = 5*fundamentallambda/2
etc.
fundamentallambda= speedsound/freq
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