An object with a volume 150 ml is found floating in water with 60% of its volume submerged.

Question

What is the density of the object

Answer 1

To find the density of the object, we will need to know the mass of the object.

Given that 60% of the object's volume is submerged in water, the volume of water displaced by the object is 150 ml x 60% = 90 ml.

Using Archimedes' principle, the volume of water displaced by the object is equal to the volume of the object submerged, which is also equal to the volume of the object in the water.

The density of water is 1 g/ml, so the mass of the object can be calculated as follows:

Volume of water displaced = 90 ml
Mass of water displaced = 90 g

Since 90 g of water is being displaced by the object, the mass of the object is 90 g.

Density = Mass / Volume
Density = 90 g / 150 ml
Density = 0.6 g/ml

Therefore, the density of the object is 0.6 g/ml.