An object of mass 50kg is placed on inclined plane at an angle of 30 degrees to the horizontal. The height of the plane is 250cm and it's length is 500cm. What is the workdone in moving the object down the plane?

Answer 1

assuming no friction, gravity does all the work and it is the change in potential energy

m g h = 50 * 9.81 * .250 Joules

Answer 2

I response

Answer 3

Please can some one help me to solve this assignment

Answer 4

F=mgcos@= 50*9.81*sin30= 424.8N
H=250cm= 2.5m
W=F*h = 424.8*2.5= 1062 J

Answer 5

W= f*s*cos 50*1250*0.9=56250

Answer 6

Mass 50kg
Degree 60
H=300cm=3m
L=100cm=1m
Work done (g=10m\s)
F=

Answer 7

F-mgsintheta=ma
Where F=force that tends to move it upward.
Mgsintheta= force that tends to move it downward.a=Acceleration
500-50×10sin30°=ma
500-250=50a
a=5m/s^2.
W=F×d=ma×d
50×5×500×10^-2
=50×5×5
=1250 Nm