An object of mass 10kg is placed on an inclined plane at 30 degree to the horizontal, calculate the reaction between the two surfaces and the coefficient of static friction

Answer 1

normal force: mg*cosTheta=10*9.8*1/2*sqrt3

Answer 2

force down the plane: mg*sin30=1/2*10*9.8
if it is not moving, this has to eqkual frection force.
friction force=mg*coefficent*cos30
or coefficent= sin30/cos30=tangent(30 deg)

Answer 3

I don't understand

Answer 4

confused

Answer 5

Don't know that's why am asking