An object of mass 10kg is placed on an inclined plane at 30 degree to the horizontal. Calculate the reaction between two surface and what is the coefficient of static friction.

Answer 1

normal force = m g cos 30
so
friction force </= mu m g cos 30

can only say less than if object is not moving.

component of weight down slope = m g sin 30

so if no other forces are acting
m g sin 30 </= mu m g cos 30
or
mu >/= tan 30

Answer 2

M*g = 10 * 9.8 = 98 N.

Fp = 98*sin30 = 49 N.

Fn = 98*Cos30 = 84.9 N.

Fp-u*Fn = M*a.
49-84.9u = 10*0 = 0
u = 0.58

Answer 3

please throw more light in this question please.

Answer 4

Reaction btwn surfaces :R=W cos è
Was not fully explained.

Answer 5

Dis doesn't seem like an answer

Answer 6

An object of mass 10kg is placed on inclined surface 30 degree to horizontal surface .Find Normal force ?

Normal force
N

Answer 7

An object of mass 10kg is placed on inclined surface 30 degree to horizontal surface .Find Normal force ?

Normal force
N