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An object of mass 10kg is placed on an inclined plane at 30 degree to the horizontal. Calculate the reaction between two surfac...Asked by Sandra
An object of mass 10kg is placed on an inclined plane at 30 degree to the horizontal, calculate the reaction between the two surfaces and the coefficient of static friction
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Answered by
bobpursley
normal force: mg*cosTheta=10*9.8*1/2*sqrt3
Answered by
bobpursley
force down the plane: mg*sin30=1/2*10*9.8
if it is not moving, this has to eqkual frection force.
friction force=mg*coefficent*cos30
or coefficent= sin30/cos30=tangent(30 deg)
if it is not moving, this has to eqkual frection force.
friction force=mg*coefficent*cos30
or coefficent= sin30/cos30=tangent(30 deg)
Answered by
Ayo
I don't understand
Answered by
...
confused
Answered by
Alimi anuoluwapo
Don't know that's why am asking
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