An object of mass 0.5kg is rotated in horizontal circle by a string of length 1m,the maximum tension in the string before it breaks is 50N.What is the greatest number of revolution per second of the object?

Answer 1

tension=mw^2/r
50=.5*w^2/1
w^2=100
w=10 rad/sec=10/2PI rev/sec

Answer 2

why is length of the string equal to the radius pls explain with example

Answer 3

isnt the formula mv^2/r?

Answer 4

tension=mw^2/r
50=.5*w^2/1
w^2=100
w=10 rad/sec=10/2PI rev/sec