an object of mass 0.1kg is rotated in a horizontal circle by a string 1m long. the maximum tension in the string before it breaks is 50N.what is its maximum frequency reached?
7 answers
0.28s??
no the answer is 1.6 revolutions per second
F = m v^2/r
50 = .1 v^2/1
v^2 = 500
v =10 sqrt 5
circumference = 2 pi r = 2 pi
time around circle = 2 pi /10 sqrt 5
frequency = 1/time = (5/pi) sqrt 5
f = 3.55
50 = .1 v^2/1
v^2 = 500
v =10 sqrt 5
circumference = 2 pi r = 2 pi
time around circle = 2 pi /10 sqrt 5
frequency = 1/time = (5/pi) sqrt 5
f = 3.55
are you sure we can use length of the string 1m as the radius? and why?
Your problem statement says the string is one meter long.
hmmm...ok thanks :)
Sry, I misunderstand the question. F=3.55
2 answers