An object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction when its x-coordinate is 2.91 cm. If its x-coordinate 1.85 s later is −5.00 cm, what is its acceleration?

Answer 1

But who does acceleration in cm^2/s
Changing to meters
at t = 0
ui = 0.10 m/s
xi = 0.0291 m

at t = 1.85 s
u = 0.10 + 1.85 a
x = 0.0291 + 0.10 (1.85) + .5 a (1.85)^2 = -0.05 so solve this for a