An object moving with uniform acceleration has a velocity of 15.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 1.60 s later is -5.00 cm, what is its acceleration?

Answer 1

V = d / t = (-5-3)1.6 = -5m/s.

a = (Vf - Vo) / t,
a = (-5 - 15) / 1.6 = -12.5m/s^2.

Answer 2

Correction: V = -5cm/s, a = 12.5cm/s^2.