Vx = (36 - 6t)^.5 at t = 1, it is sqrt(30)
Vy = 4t at t = 1, it is 4
so |V| at 1 = sqrt(46)
Ax = .5 (36-6t)^-.5 * (-6) = -3/sqrt 30 = -.55 at t = 1
Ay = 4
The velocity is increasing fast, yes, C
An object moves in the xy-plane so that its velocity vector for 0 <= t <= 10 is (√(36-6t), 4t). Which of these statements is true about the object at t = 1?
A. The object is at rest.
B. The speed of the object is √30 + 4.
C. The object is speeding up.
D. The object is slowing down.
My answer is C.
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