The height of each is
h1=78+(-5)t-4.9t^2
h2=0+50t-4.9t^2
set them equal, solve for t.
Then put time t into either, to solve for final height.
An object is thrown downward with an initial speed of 5 m/s from a height of 78 m above the ground. At the same instant, a second object is propelled vertically from ground level with a speed of 50 m/s.
The acceleration of gravity is 9.8 m/s2. At what height above the ground will the two objects pass each other?
Answer in units of m.
2 answers
The acceleration due to gravity on planet X is
one fifth that on the surface of the earth.
If it takes 3.9 s for an object to fall a certain
distance from rest on earth, how long would
it take to fall the same distance on planet X?
one fifth that on the surface of the earth.
If it takes 3.9 s for an object to fall a certain
distance from rest on earth, how long would
it take to fall the same distance on planet X?
1 answer