just calculate their heights at time t. You want
85-15t-4.9t^2 = 29t-4.9t^2
The graphs shown here might help visualize things:
http://www.wolframalpha.com/input/?i=85-15t-4.9t^2+%3D+29t-4.9t^2
An object is thrown downward with an initial
speed of 15 m/s from a height of 85 m above
the ground. At the same instant, a second
object is propelled vertically up from ground
level with a speed of 29 m/s.
At what height above the ground will the
two objects pass each other? The acceleration
of gravity is 9.8 m/s
2
.
Answer in units of m.
1 answer
1 answer