An object is released to fall from height of 100m. At the same time another object is projected vertically upwards with velocity of 40m /s.

(i) Calculate the time taken before the objects meet
(ii) At what height do the objects meet

1 answer

(i) The time taken before the objects meet can be calculated using the equation:

t = (2h)/(u + v)

where h is the height of the object, u is the initial velocity of the object falling, and v is the initial velocity of the object projected upwards.

In this case, h = 100m, u = 0m/s, and v = 40m/s.

Therefore, t = (2*100)/(0 + 40) = 5 seconds.

(ii) The objects will meet at a height of 100m, since the object falling from a height of 100m will take 5 seconds to reach the ground, and the object projected upwards will take 5 seconds to reach a height of 100m.