Asked by nano
an object is observed to fall from a bridge, striking the water below 3.03s ...with what velocitydid it strike the water?what was the average velocity during the fall?how high is the bridge?
Answers
Answered by
Victoria
"with what velocity did it strike the water?"
final velocity = initial velocity+ (acceleration * time)
initial velocity is zero because it fell off a bridge.
acceleration is 9.8 (gravity) because it was falling.
time is 3.03
0 + (3.03 x 9.8) = final velocity
the average velocity is your final velocity plus your initial velocity divided by 2
which is just your final velocity divided by 2 because your initial velocity was zero.
how high is the bridge?
distance the object fell= average velocity x time
final velocity = initial velocity+ (acceleration * time)
initial velocity is zero because it fell off a bridge.
acceleration is 9.8 (gravity) because it was falling.
time is 3.03
0 + (3.03 x 9.8) = final velocity
the average velocity is your final velocity plus your initial velocity divided by 2
which is just your final velocity divided by 2 because your initial velocity was zero.
how high is the bridge?
distance the object fell= average velocity x time
Answered by
nano
thank you very much
Answered by
nano
why u divide the final velocity by 2?
Answered by
nano
ahaaaaaa i understand
Answered by
nano
could u give me the answers for check please
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