Asked by Elle

An object is placed in front of a converging lens in such a position that the lens (f = 13.2 cm) produces a real image located 23.5 cm from the lens. Then, with the object remaining in place, the lens is replaced with another converging lens (f = 18.8 cm). A new, real image is formed. What is the image distance of this new image?


I know that I need to use the thin lens equation, but I'm not sure how to start this problem. Please help!
Answered by Anonymous
5.71
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