An object is placed in front of a converging lens in such a position that the lens (f = 13.2 cm) produces a real image located 23.5 cm from the lens. Then, with the object remaining in place, the lens is replaced with another converging lens (f = 18.8 cm). A new, real image is formed. What is the image distance of this new image?

I know that I need to use the thin lens equation, but I'm not sure how to start this problem. Please help!

1 answer

5.71