An object initially traveling at a velocity of 20.0 meters per second undergoes uniform acceleration for 5.0 seconds, reaching a final velocity of 50.0 meters per second. What is the acceleration of the object?(1 point)

Question

Responses

6.0 m/s2
6.0 m/s 2

4.0 m/s2
4.0 m/s 2

10.0 m/s2
10.0 m/s 2

14 m/s2

Answer 1

To find the acceleration of the object, we can use the formula for acceleration \( a \):

\[ a = \frac{v_f - v_i}{t} \]

Where:

• \( v_f \) is the final velocity (50.0 m/s),
• \( v_i \) is the initial velocity (20.0 m/s), and
• \( t \) is the time (5.0 seconds).

Now, plug in the values:

\[ a = \frac{50.0 , \text{m/s} - 20.0 , \text{m/s}}{5.0 , \text{s}} = \frac{30.0 , \text{m/s}}{5.0 , \text{s}} = 6.0 , \text{m/s}^2 \]

Thus, the acceleration of the object is \( \boxed{6.0 , \text{m/s}^2} \).