An object in equilibrium has three forces exerted on it. A 30 N force acts at 90° from the x-axis and a 44 N force acts at 60° from the x-axis. What are the magnitude and direction of the third force?

Question

NO IDEA WHERE TO START

Answer 1

add these two forces, then the equilibrant is the equal and opposite force of these two.

add 30j + 44sin60 j + 44 cos60 i

check those components.

Answer 2

i got 106.21 would that be the third force?
because i have to find the third force and the degrees(counterclockwise from the +x direction)

but i don't know what angle i am looking for, for the degrees part.